2/5x^2-40=0

Solution for 2/5x^2-40=0 equation:

2/5x^2-40=0


Domain of the equation: 5x^2!=0

x^2!=0/5

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


-40*5x^2+2=0

Wy multiply elements

-200x^2+2=0

a = -200; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-200)·2
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40}{2*-200}=\frac{-40}{-400}
=1/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40}{2*-200}=\frac{40}{-400}
=-1/10
$